Calculations based on Problems on trains - Stationary object with negligible length

Problems on trains - Stationary object  with negligible length

In this section, we consider a scenario where the train is passing by a stationary object with negligible length such as a pole or a standing man.

we calculate time taken by the train to pass this object.

Formulae used  

\[Time \: taken = \frac{length \: of\: the\: train}{Speed} \]

\[speed\: km/hr = \left ( speed \times \frac{5}{18}\right )\: m/sec \]

\[speed\: m/sec = \left (speed \times \frac{18}{5} \right ) km/hr \]

Calculating time taken for a train to cross a stationary object

Formula : Time taken = length/speed

Input

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Check your output in all other similar units

Time(sec) {{tsvalue}}
Time(hr) {{thvalue}}

Calculating speed of the train crossing a stationary object

Formula : speed = length/Time

Input

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Speed(m/s) {{ssvalue}}
Speed(km/hr) {{shvalue}}

Calculating length of the train crossing a stationary object

Formula : length = speed ⨯ Time

Input

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Check your output in all other similar units

Length(m) {{lmvalue}}
Length(km) {{lkmvalue}}
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