Calculations based on Problems on trains - Stationary object with length

Problems on trains - Stationary object  with length

In this section, we consider that the stationary object has length for example, train station and try to find the time taken by the train to completely cross this object.

To do this we simply add the length of the object and train and use it to calculate time taken to cross the object.

Formulae used

Consider that length of train is 'a' and length of object is 'b' then

 collective length(l) = (a+b)

\[Time\: taken = \frac{l}{speed} \]

\[speed \: km/hr = \left ( speed \: \times \: \frac{5}{18} \right )m/sec \]

Calculating time taken for a train to cross a stationary object with length

Formula : Time taken = length(train+object)/speed

Input

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Check your output in all other similar units

Time(sec) {{tsvalue}}
Time(hr) {{thvalue}}

Calculating length of a train crossing stationary object with length

Formula : length = (time ⨯ speed) - length of object

Input

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Check your output in all other similar units

Length of train(m) {{lmvalue}}
Length of train(km) {{lkmvalue}}

Calculating length of an object which a train passes by

Formula : length = (time ⨯ speed) - length of train

Input

Reset




Check your output in all other similar units

Length of object(m) {{lmvalue}}
Length of object(km) {{lkmvalue}}
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