A cube minus B cube

a^{3}-b^{3}=(a-b)(a^{2}+b^{2}+ab)

for example 

Lets consider a= 5 and b = 3

then a3  - b3  = 53 - 33

                     = 125 - 27

                    = 98

(a-b) (a2 + b2 + ab) = (5-3)(52 +32 +5 X 3)

                                 = 2(25+9+15)

                                 = 98

Hence LHS = RHS proved

Calculate a3 - b3

Formula : a3 - b3 = (a - b)(a2 + b2 + ab)

Input

Reset

Output

Result {{result}}
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