x minus a x minus b

(x - a)(x - b)=x^{2}-(a+b)x+ab

for example 

let value of x =5  a=2 and b=3 

(x-a) = (5-2)=3                                           

(x-b)=(5-3)=2

(x-a)(x-b) = (5-2)(5-3) = 3 X 2 = 6 => LHS

x2 - (a+b)x+ab = 52 - (2+3)5 + 2X3 = 25 - 25 +6 = 6 =RHS

Therefore LHS = RHS

Calculate (x - a) (x - b)

Formula : (x - a) (x - b) = x2 - (a + b)x + ab

Input

Reset



Output

Result {{result}}
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