Method overloading:-.It is the same method name with different signatures/arguments/parameters..It is not dependent on the return type. ie; there can be any return type for the method
-----------------------------------------------Program------------------------------------------------------
package java1;
import java.util.Scanner;
public class Java1
{
int a=1,b=1,c;
int compute()
{
c=a+b;
System.out.println("sum of the numbers "+c);
return c;
}
int compute(int d)
{
c=d*b;
System.out.println("multiplication of numbers: "+c);
return c;
}
void compute(float d,int e)
{
float c;
c=d+e;
System.out.println("Sum of float and int: "+c);
}
void compute(String d,String e,char f)
{
String c=d+e+f;
System.out.println(c);
}
public static void main(String[] args)
{
Java1 j=new Java1();
Scanner sc=new Scanner(System.in);
System.out.println("enter an integer:");
int a=sc.nextInt();
j.compute();
j.compute(a);
j.compute(10.5f,5); //we need to specify the float number with--f--//otherwise the value is treated as double
j.compute("hi","hello",'a');
}
}
In the above programming example,
compute is the overloaded method having different arguments/parameters/signature with independent return type.
