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A system absorb 300 cal of heat with the result of that, the volume of the system becomes double of its initial volume and temperature changes from 273K to 546K. The work done by the system on the surrounding is 200 cal. Calculate ΔE -
A) 273 kCal
B)500 Cal
C) 100 Cal
D) -500Cal
NEET
Engineering Entrance Exams
Medical Entrance Exams
CLASS-XI (PCM)
CLASS-XI (PCB)
KVPY
NDA
NCERT
Chemistry
Thermodynamics
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