Predict the output #include <stdio.h>char * f();char a = 'a';int main(int argc, char *argv[]){ char *temp = f();printf('%%', temp);return 0;}char *f(){ return &a;}

Charitha R

Predict the output

#include <stdio.h>
char * f();
char a = 'a';

int main(int argc, char *argv[])
{ 
char *temp = f();
printf("%%", temp);
return 0;
}

char *f()
{ 
return &a;
}

Posted on by

Score

Views

Comment(s)

Please Login to post your comment or reply to comment

Predict the output #include <stdio.h>char * f();char a = 'a';int main(int argc, char *argv[]){ char *temp = f();printf("%%", temp);return 0;}char *f(){ return &a;}

Predict the output
#include <stdio.h>

char * f();
char a = 'a';

int main(int argc, char argv[])
{
char temp = f();
printf("%%", temp);
return 0;
}

char *f()
{
return &a;
}