What will be the final values of i and j in the following C code?

#include <stdio.h>

int x = 0;

int main()

{

int i = (f() + g()) | g(); //bitwise or

int j = g() | (f() + g()); //bitwise or

}

int f()

{

if (x == 0)

return x + 1;

else

return x - 1;

}

int g()

{

return x++;

}

a) i value is 1 and j value is 1
b) i value is 0 and j value is 0
c) i value is 1 and j value is undefined
d) i and j value are undefined