Predict the Op?#include <stdio.h> void solve() { int a[] = {1, 2, 3, 4, 5}; int sum = 0; for(int i = 0; i < 5; i++) { if(i % 2 == 0) { sum += *(a + i); } else { sum -= *(a + i); } } printf('%d', sum); } int main() { solve(); return 0; }

Akash M K

Predict the Op?

#include <stdio.h>
void solve() {
int a[] = {1, 2, 3, 4, 5};
int sum = 0;
for(int i = 0; i < 5; i++) {
if(i % 2 == 0) {
sum += *(a + i);
}
else {
sum -= *(a + i);
}
}
printf("%d", sum);
}
int main() {
solve();
return 0;
}