What will be the output of the following C code considering the size of a short int is 2, char is 1 and int is 4 bytes? #include stdio.h int main() { short int i = 20; char c = 97; printf('%d, %d, %d\n', sizeof(i), sizeof(c), sizeof(c + i)); return 0; }

N.S.Manikanta.R.

What will be the output of the following C code considering the size of a short int is 2, char is 1 and int is 4 bytes?

    #include stdio.h    int main()
    {
        short int i = 20;
        char c = 97;
        printf("%d, %d, %d\n", sizeof(i), sizeof(c), sizeof(c + i));
        return 0;
    }

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What will be the output of the following C code considering the size of a short int is 2, char is 1 and int is 4 bytes? #include stdio.h int main() { short int i = 20; char c = 97; printf("%d, %d, %d\n", sizeof(i), sizeof(c), sizeof(c + i)); return 0; }

What will be the output of the following C code considering the size of a short int is 2, char is 1 and int is 4 bytes?
#include stdio.h
int main()
{
short int i = 20;
char c = 97;
printf("%d, %d, %d\n", sizeof(i), sizeof(c), sizeof(c + i));
return 0;
}