#include

int main ( )

{

int a[ ] = {2, 4, 6, 8, 10};

int i, sum = 0, *b = a + 4;

for (i = 0; i

sum = sum + (*b - i) - *(b - i);

printf (“ % d \ n”, sum);

return 0;

}
Output of the program is

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