What will be the output of the following code snippet?


#include stdio.h
void solve() {
int a[] = {1, 2, 3, 4, 5};
int sum = 0;
for(int i = 0; i  5; i++) {
if(i % 2 == 0) {
sum += *(a + i);
}
else {
sum -= *(a + i);
}
}
printf("%d", sum);
}
int main() {
solve();
return 0;
}

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