If int is 2 bytes wide.What will be the output of the program?#include stdio.hvoid fun(char**);int main(){ char *argv[] = {'ab', 'cd', 'ef', 'gh'}; fun(argv); return 0;}void fun(char **p){ char *t; t = (p+= sizeof(int))[-1]; printf('%s\n', t);}

If int is 2 bytes wide.What will be the output of the program?

#include stdio.h
void fun(char**);

int main()
{
char *argv[] = {"ab", "cd", "ef", "gh"};
fun(argv);
return 0;
}
void fun(char **p)
{
char *t;
t = (p+= sizeof(int))[-1];
printf("%s\n", t);
}