What will be the output of the following psuodocode when parameters are passed by reference and dynamic scoping is assumed?a=3;void a(x){x=x*a;print(x);}void m(y){a=1;a=y-a;n(a);print(a);}void main(){m(a);}

What will be the output of the following psuodocode when parameters are passed by reference and dynamic scoping is assumed?

a=3;
void a(x)
{
x=x*a;
print(x);
}
void m(y)
{
a=1;
a=y-a;
n(a);
print(a);
}
void main()
{
m(a);
}