Paying with pointers: OUTPUT is ? #include stdio.hint main(){ int a,b; int *p1,*p2; p1=&a; p2=&b; p1++; if(p1==p2) printf('You are pointing to the same house-- %d\n',*p1); else printf('You are lost.'); return 0;}

Paying with pointers: OUTPUT is ?

#include stdio.h
int main()
{
    int a,b;
    int *p1,*p2;
    
    p1=&a;
    p2=&b;
    p1++;
    
    if(p1==p2)
        printf("You are pointing to the same house-- %d\n",*p1);
    else
        printf("You are lost.");
    
    return 0;
}

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Paying with pointers: OUTPUT is ? #include stdio.hint main(){ int a,b; int *p1,*p2; p1=&a; p2=&b; p1++; if(p1==p2) printf("You are pointing to the same house-- %d\n",*p1); else printf("You are lost."); return 0;}

Paying with pointers: OUTPUT is ?

#include stdio.h

int main()
{
int a,b;
int p1,p2;

p1=&a;
p2=&b;
p1++;

if(p1==p2)
printf("You are pointing to the same house-- %d\n",*p1);
else
printf("You are lost.");

return 0;
}