#include stdio.h
#include stdlib.h
int main () {
   int i, n=3;
   int *a;
 printf("Number of elements are:%d\n",n);
   a = (int*)calloc(n, sizeof(int));
   printf("number of %d are\n",n);
   for( i=0 ; i  n ; i++ ) {
      a[i]=2+i;
   }
   for( i=0 ; i  n ; i++ ) {
      printf("%d ",a[i]);
   }
   free( a );
   return(0);
}

what is the output of following calloc function of c