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#include stdio.h void solve() { int a[] = {1, 2, 3, 4, 5}; int sum = 0; for(int i = 0; i 5; i++) { if(i % 2 == 0) { sum += *(a + i); } else { sum -= *(a + i); } } printf("%d", sum); } int main() { solve(); return 0; }
a = [1, 2, 3]a = tuple(a)a[0] = 2print(a)