#include <stdio.h>void solve() {int a[] = {1, 2, 3, 4, 5};int sum = 0;for(int i = 0; i < 5; i++) {if(i % 2 == 0) {sum += *(a + i);}else {sum -= *(a + i);}}printf("%d", sum);}int main() {solve();return 0;}
#include <stdio.h>void solve() {printf("%d ", 10/ 2);printf("%f", 10.0/ 2);}int main() {solve();return 0;}