Sookshmas | Recent Posts

Posted on October 17,2022 at 09:42 PM by Dinesh maanju

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1Comment(s)

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The packaging of chromatin at higher level requires additional set of proteins that is known as

Posted on October 17,2022 at 09:25 PM by Ovesh naqvi

Medical Entrance Exams-Medium-Hindi

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1Comment(s)

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Predict the O/p??

#include <stdio.h>

int main()
{
int x = 21;
x %= 3;
printf("%d",x);
return 0;
}

Posted on October 17,2022 at 09:20 PM by Akash M K

GMIT Davangere

Artificial intelligence

Programming Languages

Analysis

20Score(s)

1Comment(s)

90View(s)

#include<stdio.h>
int main()
{
    double x = 30.5;
    x %= 20.0;
    printf("%d",x);
   return 0;
}

What will be the output

Posted on October 17,2022 at 09:16 PM by Soumya V h

11Score(s)

0Comment(s)

54View(s)

What will be the output?

#inlcude<stdio.h>int main()
{
int n,i,j;
printf(" How many rows you want in your pyramid \n");
scanf("%d",&n);
for(i=0; i<=n;i++)
{
for(j=0; j<2*n-1;j++)
{
if(j>n-(i-1) && j<n+(i-1)
{
  printf(" ");
}
else
  printf(" ");
}
  printf("\n");
}
return 0;
}

Posted on October 17,2022 at 08:57 PM by Vidyarani Patil

GMIT Davangere

Artificial intelligence

18Score(s)

0Comment(s)

78View(s)

What is the output of following code?

#include <stdio.h>
int main()
{
    int i;
    i = 10> 12 ? 15 : 1 != 2 < 5 ? 20 : 30;
    printf("Value of x:%d", i);
    return 0;
}

Posted on October 17,2022 at 08:23 PM by Shreya B

Engineering-CS

Engineering-IS

SEM-II

Artificial intelligence

C Language

Engineering-IT

22Score(s)

0Comment(s)

81View(s)

Posted on October 17,2022 at 08:03 PM by Dhruv Sagathiya

Medical Entrance Exams

NEET

Engineering Entrance Exams

14Score(s)

0Comment(s)

41View(s)

Posted on October 17,2022 at 07:45 PM by Emdadul Islam

Medical Entrance Exams

NCERT

CLASS-XII (PCB)

CLASS-XI (PCB)

Engineering Entrance Exams

15Score(s)

1Comment(s)

34View(s)

Posted on October 17,2022 at 06:48 PM by Ashutosh Jaiswal

Engineering Entrance Exams

11Score(s)

0Comment(s)

54View(s)

Posted on October 17,2022 at 06:10 PM by Priyanshu Sharma

JEE-Main

JEE-Advance

KVPY

Board of Secondary Education Rajasthan

CBSE Previous Year Question Paper

8Score(s)

1Comment(s)

22View(s)

Recent Posts

The packaging of chromatin at higher level requires additional set of proteins that is known as

Predict the O/p??
#include <stdio.h>

int main()
{
int x = 21;
x %= 3;
printf("%d",x);
return 0;
}

#include<stdio.h>
int main()
{
double x = 30.5;
x %= 20.0;
printf("%d",x);
return 0;
}

What will be the output

What will be the output?
#inlcude<stdio.h>
int main()
{
int n,i,j;
printf(" How many rows you want in your pyramid \n");
scanf("%d",&n);
for(i=0; i<=n;i++)
{
for(j=0; j<2*n-1;j++)
{
if(j>n-(i-1) && j<n+(i-1)
{
printf(" ");
}
else
printf(" ");
}
printf("\n");
}
return 0;
}

What is the output of following code?
#include <stdio.h>
int main()
{
int i;
i = 10> 12 ? 15 : 1 != 2 < 5 ? 20 : 30;
printf("Value of x:%d", i);
return 0;
}

Recent Posts

The packaging of chromatin at higher level requires additional set of proteins that is known as

Predict the O/p??#include <stdio.h> int main() { int x = 21; x %= 3; printf("%d",x); return 0; }

#include<stdio.h>int main(){ double x = 30.5; x %= 20.0; printf("%d",x); return 0;}What will be the output

What will be the output?#inlcude<stdio.h>int main(){int n,i,j;printf(" How many rows you want in your pyramid \n");scanf("%d",&n);for(i=0; i<=n;i++){for(j=0; j<2*n-1;j++){if(j>n-(i-1) && j<n+(i-1){ printf(" ");}else printf(" ");} printf("\n");}return 0;}

What is the output of following code?#include <stdio.h> int main() { int i; i = 10> 12 ? 15 : 1 != 2 < 5 ? 20 : 30; printf("Value of x:%d", i); return 0; }

Predict the O/p??
#include <stdio.h>

int main()
{
int x = 21;
x %= 3;
printf("%d",x);
return 0;
}

#include<stdio.h>
int main()
{
double x = 30.5;
x %= 20.0;
printf("%d",x);
return 0;
}

What will be the output

What will be the output?
#inlcude<stdio.h>
int main()
{
int n,i,j;
printf(" How many rows you want in your pyramid \n");
scanf("%d",&n);
for(i=0; i<=n;i++)
{
for(j=0; j<2*n-1;j++)
{
if(j>n-(i-1) && j<n+(i-1)
{
printf(" ");
}
else
printf(" ");
}
printf("\n");
}
return 0;
}

What is the output of following code?
#include <stdio.h>
int main()
{
int i;
i = 10> 12 ? 15 : 1 != 2 < 5 ? 20 : 30;
printf("Value of x:%d", i);
return 0;
}