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#include<stdio.h>main()
{
char c = 'A'+255;
printf("%c", c) ;
}

What is the output of this code snippet?

Posted on September 12,2022 at 07:00 AM by Aisiri p

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Posted on September 12,2022 at 06:57 AM by Harshit mangal

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Why don't we use "return0" in Ubuntu Terminal ?

Posted on September 11,2022 at 10:38 PM by C V Vibhav

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Posted on September 11,2022 at 07:55 PM by Harshit mangal

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Posted on September 11,2022 at 06:40 PM by Vikas Singh

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Describe Wild Pointers in C?

Answer: Uninitialized pointers in the C code are known as Wild Pointers. They point to some arbitrary memory location and can cause bad program behavior or program crash.

Posted on September 11,2022 at 06:28 PM by H.M.Mahonnath

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What is the output of the following program.

#include <stdio.h>int main() {
   int i, j, rows;
   printf("Enter the number of rows: ");
   scanf("%d", &rows);
   for (i = 1; i <= rows; ++i) {
      for (j = 1; j <= i; ++j) {
         printf("* ");
      }
      printf("\n");
   }
   return 0;
}

Posted on September 11,2022 at 03:09 PM by Deepak Patil

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Posted on September 11,2022 at 10:06 AM by Kanishka gupta

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Recent Posts

#include<stdio.h>
main()
{
char c = 'A'+255;
printf("%c", c) ;
}
What is the output of this code snippet?

Why don't we use "return0" in Ubuntu Terminal ?

Describe Wild Pointers in C?

Answer: Uninitialized pointers in the C code are known as Wild Pointers. They point to some arbitrary memory location and can cause bad program behavior or program crash.

What is the output of the following program.

#include <stdio.h>
int main() {
int i, j, rows;
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (i = 1; i <= rows; ++i) {
for (j = 1; j <= i; ++j) {
printf("* ");
}
printf("\n");
}
return 0;
}

Recent Posts

#include<stdio.h>main(){char c = 'A'+255;printf("%c", c) ;}What is the output of this code snippet?

Why don't we use "return0" in Ubuntu Terminal ?

Describe Wild Pointers in C?Answer: Uninitialized pointers in the C code are known as Wild Pointers. They point to some arbitrary memory location and can cause bad program behavior or program crash.

What is the output of the following program.#include <stdio.h>int main() { int i, j, rows; printf("Enter the number of rows: "); scanf("%d", &rows); for (i = 1; i <= rows; ++i) { for (j = 1; j <= i; ++j) { printf("* "); } printf("\n"); } return 0;}

#include<stdio.h>
main()
{
char c = 'A'+255;
printf("%c", c) ;
}
What is the output of this code snippet?

Describe Wild Pointers in C?

Answer: Uninitialized pointers in the C code are known as Wild Pointers. They point to some arbitrary memory location and can cause bad program behavior or program crash.

What is the output of the following program.

#include <stdio.h>
int main() {
int i, j, rows;
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (i = 1; i <= rows; ++i) {
for (j = 1; j <= i; ++j) {
printf("* ");
}
printf("\n");
}
return 0;
}