#include stdio.hFind the output of the following code :-void solve() {int a[] = {1, 2, 3, 4, 5};int sum = 0;for(int i = 0; i 5; i++) {if(i % 2 == 0) {sum += *(a + i);}else {sum -= *(a + i);}}printf("%d", sum);}int main() {solve();return 0;}
#include stdio.hvoid inline func1(int a, int b){printf ("a=%d and b=%d\n", a, b);}int inline func2(int x){return x*x;}int main(){int tmp;func1(1,4);tmp = func2(6);printf("square val=%d\n", tmp);return 0;}
int main(){int a=25;while(a = 27){printf("%d ", a);a++;}return 0;}
The loop runs till the value?
Public class Solution{ Public static void main(String args[]){ Int i; for(i = 1; i 20; i++){ if(i 3) continue; } System.out.println(i); }}#includestdio.hstruct temp{int a;}s;void change(struct temp)main(){s.a=10;change(s);printf("%d\n,s.a);}void change(struct temp s){s.a=1;}
#include stdio.hint main(){int i = 0;do{i++;if (i == 2)continue;printf("In while loop ");} while (i 2);printf("%d\n", i);}